![Antonio Omatos on Twitter: "Solve the equation: 8*(0.8)^(n-2)=1 ---> log (1/8)/log(0.8)+2 =11.31... Therefore the solution is 11 squares. Nice problem 😀😀… " Antonio Omatos on Twitter: "Solve the equation: 8*(0.8)^(n-2)=1 ---> log (1/8)/log(0.8)+2 =11.31... Therefore the solution is 11 squares. Nice problem 😀😀… "](https://pbs.twimg.com/media/Dkriw5vW4AINeWx.jpg)
Antonio Omatos on Twitter: "Solve the equation: 8*(0.8)^(n-2)=1 ---> log (1/8)/log(0.8)+2 =11.31... Therefore the solution is 11 squares. Nice problem 😀😀… "
![The Biological bulletin. Biology; Zoology; Biology; Marine Biology. H 0.6 0.8 1.0 1.2 1.4 1.6 Log Dorsal Mantle Length (mm) 1.8 Figure 5. Plot of the log rate of thrust increase The Biological bulletin. Biology; Zoology; Biology; Marine Biology. H 0.6 0.8 1.0 1.2 1.4 1.6 Log Dorsal Mantle Length (mm) 1.8 Figure 5. Plot of the log rate of thrust increase](https://c8.alamy.com/comp/RHM9Y9/the-biological-bulletin-biology-zoology-biology-marine-biology-h-06-08-10-12-14-16-log-dorsal-mantle-length-mm-18-figure-5-plot-of-the-log-rate-of-thrust-increase-versus-the-log-of-dorsal-mantle-length-each-point-represents-the-highest-rate-of-thrust-increase-for-one-squid-log-rate-of-thrust-increase-was-regressed-against-the-log-of-dml-using-an-ordinary-least-squares-method-the-regression-equation-is-located-in-the-upper-left-corner-of-the-plot-h-hatchling-stage-squids-jl-juvenile-1-stage-j2-juvenile-2-stage-nentially-during-ontogeny-to-between-100-and-1000-mn-s-RHM9Y9.jpg)
The Biological bulletin. Biology; Zoology; Biology; Marine Biology. H 0.6 0.8 1.0 1.2 1.4 1.6 Log Dorsal Mantle Length (mm) 1.8 Figure 5. Plot of the log rate of thrust increase
![Given log 4 = .60206 and log 3 = .4771213 , find the logarithms of .8, .003, .0108 , and (.00018)^ 17 . Given log 4 = .60206 and log 3 = .4771213 , find the logarithms of .8, .003, .0108 , and (.00018)^ 17 .](https://haygot.s3.amazonaws.com/questions/1662378_1731023_ans_b314a49f3b2e450cbe5644bd63a23297.png)
Given log 4 = .60206 and log 3 = .4771213 , find the logarithms of .8, .003, .0108 , and (.00018)^ 17 .
![Log (ω) versus log (ac) for Ba 2-x Cu x Co 2 Cr y Fe 28-y O 46 [x=0.0,... | Download Scientific Diagram Log (ω) versus log (ac) for Ba 2-x Cu x Co 2 Cr y Fe 28-y O 46 [x=0.0,... | Download Scientific Diagram](https://www.researchgate.net/profile/Muhammad-Khan-474/publication/321711514/figure/fig5/AS:570345757343744@1512992433103/Log-o-versus-log-ac-for-Ba-2-x-Cu-x-Co-2-Cr-y-Fe-28-y-O-46-x00-01-02-03.png)
Log (ω) versus log (ac) for Ba 2-x Cu x Co 2 Cr y Fe 28-y O 46 [x=0.0,... | Download Scientific Diagram
![105 32 - log3 8 log3 ... 9 — 5 105 3 105 3 50. log 0.8 54. log 1.5 58. log É = 3 log3 2 105 8 - [PDF Document] 105 32 - log3 8 log3 ... 9 — 5 105 3 105 3 50. log 0.8 54. log 1.5 58. log É = 3 log3 2 105 8 - [PDF Document]](https://demo.fdocuments.in/img/378x509/reader018/reader/2020011609/5c0db1f909d3f20b788bd78e/r-1.jpg)
105 32 - log3 8 log3 ... 9 — 5 105 3 105 3 50. log 0.8 54. log 1.5 58. log É = 3 log3 2 105 8 - [PDF Document]
![C) 1/4 if log 2.log(2\"-1) and log(20+3) are in AP, then n 5 dy of ce is getic 0.8 ven ion is equal to (B) log, (C) log, 5 C) 1/4 if log 2.log(2\"-1) and log(20+3) are in AP, then n 5 dy of ce is getic 0.8 ven ion is equal to (B) log, (C) log, 5](https://toppr-doubts-media.s3.amazonaws.com/images/3816434/7a68d535-b153-4ccc-b0e0-29f3dc7a6aa6.jpg)